B.y(k) y(k-1)y(k-2)=2f(k)C.y(k) ky(k-2)=f(1-k) 2f(k-1D.y(k) 2y(k-1)=2|f(k)
B、y(k) y(k-1)y(k-2)=2f(k)
C、y(k) ky(k-2)=f(1-k) 2f(k-1
D、y(k) 2y(k-1)=2|f(k)
发布时间:2025-10-20 14:35:45
B、y(k) y(k-1)y(k-2)=2f(k)
C、y(k) ky(k-2)=f(1-k) 2f(k-1
D、y(k) 2y(k-1)=2|f(k)