下面代码的执行结果是: ( )ls= ["2020", "20.20", "Pyhon"] ls.append(2020)Is append([2020, "2020"] )print(ls)
A、['2020','20.20','Python',2020,2020,'2020']
B、['2020','20.20','Python',2020]
C、['2020','20.20','Python',2020,[2020,'2020']]
D、['2020','20.20','Python',2020,['2020']]
发布时间:2025-07-17 01:02:41